Asked by Hayley
The area of an equilateral triangle is decreased to 9/16 of its original amount. How does its new area compare to its original area?
Answers
Answered by
Reiny
You already stated the answer.
It is 9/16 of its original area.
You probably meant to ask:
How do the sides of the reduced triangle compare to the original sides?
Remember what I told you in a question similar to this?
"The area of similar shapes is proportional to the square of their corresponding sides"
area of new : area of original = side^2 of new : side^2 of old
= 9/16
= 3^2 / 4^2
so the new side is 3/4 of the old side
It is 9/16 of its original area.
You probably meant to ask:
How do the sides of the reduced triangle compare to the original sides?
Remember what I told you in a question similar to this?
"The area of similar shapes is proportional to the square of their corresponding sides"
area of new : area of original = side^2 of new : side^2 of old
= 9/16
= 3^2 / 4^2
so the new side is 3/4 of the old side
Answered by
Hayley
No this was the exact question in my textbook
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