Asked by john
3 bolts and 3 nuts are in a box. 2 parts are chosen at random. Find the probability that 1 is a bolt and 1 is a nut.
Answers
Answered by
Reiny
number of ways to choose 2 from 5 items = C(5,2) = 10
number of ways to choose 1 bolt from3 and 1 nut from 3
= C(3,1) * C(3,1) = 9
prob(your event) = 9/10
number of ways to choose 1 bolt from3 and 1 nut from 3
= C(3,1) * C(3,1) = 9
prob(your event) = 9/10
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