Question
What is the molality of a solution consisting of 34.0 mL of benzene (C6H6; d = 0.877 g/mL) in 187 mL of hexane (C6H14 ; d = 0.660 g/mL)?
Answers
bobpursley
from the densities, figure the grams of each.
molality=(gramsBenzene/molmassC6H6)/kg of hexane
notice the denominator is in kg.
molality=(gramsBenzene/molmassC6H6)/kg of hexane
notice the denominator is in kg.
Samrawit
654f