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What is the molality of a solution consisting of 34.0 mL of benzene (C6H6; d = 0.877 g/mL) in 187 mL of hexane (C6H14 ; d = 0.660 g/mL)?
8 years ago

Answers

bobpursley
from the densities, figure the grams of each.

molality=(gramsBenzene/molmassC6H6)/kg of hexane

notice the denominator is in kg.
8 years ago
Samrawit
654f
3 years ago

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