Asked by Jake
What is the molality of a solution formed by dissolving 1.95 mol of KCl in 17.0 mol of water (MM of water = 18.02 g/mol), answer in 3 sigfigs?
Answers
Answered by
DrBob222
m = mols/kg solvent
m = 1.95/(18.02*17.0)
m = 1.95/(18.02*17.0)
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