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If the radius of a sphere is increasing at a constant rate of 4 cm/sec, then the volume is increasing at a rate of ???? cm^3/sec when the radius is 5 cm.
8 years ago

Answers

Steve
v = 4/3 pi r^3
dv/dt = 4 pi r^2 dr/dt

now just plug in your numbers ...
8 years ago
NIKKI
I got 264586.8
by calculating

268.08x 986.96

where did I go wrong?

Thanks steve
8 years ago
Steve
where ever did you get those numbers?

4 pi r^2 dr/dt
= 4 * pi * 5^2 * 4
= 400 pi cm^3/s
8 years ago

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