Asked by NIKKI

If the radius of a sphere is increasing at a constant rate of 4 cm/sec, then the volume is increasing at a rate of ???? cm^3/sec when the radius is 5 cm.

Answers

Answered by Steve
v = 4/3 pi r^3
dv/dt = 4 pi r^2 dr/dt

now just plug in your numbers ...
Answered by NIKKI
I got 264586.8
by calculating

268.08x 986.96

where did I go wrong?

Thanks steve
Answered by Steve
where ever did you get those numbers?

4 pi r^2 dr/dt
= 4 * pi * 5^2 * 4
= 400 pi cm^3/s
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions