Ok, that will do it, but natural logs are better...
amount=60 e^(-.693*84/28)
The half-life of Strontium-90 is 28 a. If 60 g of this isotope is currently in a sample of soil, estimate the amount in the same sample 84 a later.
So I did a=60g(1/2)^84/28
But I don't know if thats correct.
Thank for your help!
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