Asked by DEE
A REGULAR PENTAGON AND A SQUARE ABFG ARE FORMED ON OPPOSITE SIDE OF AB FIND ANGLE BCF.
Answers
Answered by
Steve
In triangle BCF, sides BC and BF are equal, since they are both the length s of one side of the pentagon.
angle B is 18° (90°-72°, the exterior angle of the pentagon)
So, since BCF is isosceles, angle BCF = (180-18)/2 = 81°
angle B is 18° (90°-72°, the exterior angle of the pentagon)
So, since BCF is isosceles, angle BCF = (180-18)/2 = 81°
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