Ask a New Question
Search
Asked by
gift
Abcde is a regular pentagon .find the angles of a triangle ADC?
Answers
Answers
Answered by
oobleck
all the angles of the pentagon are 108°
∆ABC and ADE are isosceles, with angles of 108,36,36°
So, ∆ADC is isosceles with angles of 72,72,36°
Related Questions
Related
In a pentagon ABCDE, AB = AE, BC = ED and BD = EC. Prove that AC = AD.
Regular pentagon ABCDE is inscribed in circle O. What is the number of degrees in the measure of ang...
Pentagon ABCDE ~ Pentagon FGHIJ. Find BC for GH =12, IJ = 15 and DE = 10
ABCDE is a regular pentagon. On the outside of AB, we construct a square ABFG. What is the measure (...
ABCDE is a regular pentagon. FAD is an equilateral triangle, such that points F and E are on the sam...
The convex pentagon ABCDE has a right angle at B,AB=BC andCD=DE=EA=1cm,AC=2cm.If AC and ED are paral...
ABCDE is a Pentagon with BE parallel to CD and BC parallel to DE. BC is perpendicular to CD. if the...
ABCDE is a Pentagon . AB\\CD, angle A, angle E ,angle D are in ratio 4:2:3.Find angle A ,Angle E an...
ABCDE is a regular pentagon. DEF is a straight line. Calculate ( a ) angle AEF,