Asked by mohammad
what volume of carbondioxide is produced when 10g of Hcl reacts completely with caco3
caco3+2HCl=cacl2+H2o+Co2
moles ofHCl=10/36.5=0.27
volume:volume
2HCl:CO2
2:1
24000*2:24000
480000:24000
2700:x
x=1350cm3
caco3+2HCl=cacl2+H2o+Co2
moles ofHCl=10/36.5=0.27
volume:volume
2HCl:CO2
2:1
24000*2:24000
480000:24000
2700:x
x=1350cm3
Answers
Answered by
Damon
.27 mols HCl agree
so
.135 mols CO2--- agree
at standard temp and pressure a mol is 22.4 liters
.135 mol*22.4 liters/mol= 3 liters
a liter is 1000 cm^3
so I get 3,000 cm^3
so
.135 mols CO2--- agree
at standard temp and pressure a mol is 22.4 liters
.135 mol*22.4 liters/mol= 3 liters
a liter is 1000 cm^3
so I get 3,000 cm^3
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