Asked by Dom

Problem:

An excited hydrogen atom could, in principle, have a radius of 2.50 mm .
________
Part A:

What would be the value of n for a Bohr orbit of this size?

Answer--> n= 6.87×103
_______
Part B

What would its energy be?

Answer--> E=_______eV

[Note: I got 4.61x10^-26 for part B but I got it wrong 3 times. Please help]



Answered by Dom
Part A answer is n= 6.87x10^3

Answered by Scott
Rn = n^2 * R1

2.50E-3 m = n^2 * .53E-10 m


En = (13.6 / n^2) eV
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