Ask a New Question

Question

A uniform rod of mass 444 g and length 1.41 m is pivoted about one end and oscillates in a vertical plane. Find the period of oscillations if the amplitude of the motion is small. The acceleration of gravity is 9.8 m/s^2.
Answer in units of s.
8 years ago

Answers

Related Questions

A 0.20 m uniform bar has a mass of 0.75 kg and is released from rest in the vertical position, as... A 0.95 m rod with uniform mass distribution runs along the x axis with its left end at the origin. A... A uniform rod of mass M = 0.245kg and length L = 0.49m stands vertically on a horizontal table. It i... A uniform rod of mass M = 326 kg is in the shape of a semicircle of radius R = 6 m. Calculate the ma... A uniform rod of mass M = 437.0 g and length L = 37.1 cm stands vertically on a horizontal table. It... A uniform rod of mass M and length d is initially at rest on a horizontal and frictionless table con... A uniform rod of mass 2 kg and length 1.41 m is hinged at its top end and allowed to swing in the ve... A uniform rod of mass 2.0 kg and length 8.4 m is free to rotate about one end (see the following fig... A uniform rod of mass M and length d is initially at rest on a horizontal and frictionless table con... A uniform rod AB of mass 60g is balanced horizontally about a knife edge at distance of 3cm from end...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use