Asked by DEAR GOD SOMEONE HELP ME PLEASE
                Draw a complete Lewis Structure (showing all bonds and lone pairs) for a molecule with the general formula AX4, if A was from group 4A and X was from group 7A
            
            
        Answers
                    Answered by
            Doc
            
    Drawing lewis structures
1. Calculate Valence Number (total #valence electrons - from group number)
2. Calculate Octet Number (total #electrons after bonding - always 8 (nonmetals) except for hydrogen and complex substrates => 2)
3. Calculate Bond Number (#Cov. Bonds = (V - O)/2 )
1. Valence# = 1A + 4X = 1(4) + 4(7) = 32 (sum is always even no.; complex substrates => Valence = 1 => like a methyl group or iso-propyl group; elements (non-metals)
2. Octet# = 1A + 4X = 1(8) + 4(8)= 40 (all nonmetal elements have octet (8) except for hydrogen and complex substrates = 2)
3. Bond# = (V#-O#)/2 =(40-32)/2 = 8/2 = 4 Cov Bonds
DRAW STRUCTURE => A is central element, X substrates.
X
!
X-A-X
!
X
    
1. Calculate Valence Number (total #valence electrons - from group number)
2. Calculate Octet Number (total #electrons after bonding - always 8 (nonmetals) except for hydrogen and complex substrates => 2)
3. Calculate Bond Number (#Cov. Bonds = (V - O)/2 )
1. Valence# = 1A + 4X = 1(4) + 4(7) = 32 (sum is always even no.; complex substrates => Valence = 1 => like a methyl group or iso-propyl group; elements (non-metals)
2. Octet# = 1A + 4X = 1(8) + 4(8)= 40 (all nonmetal elements have octet (8) except for hydrogen and complex substrates = 2)
3. Bond# = (V#-O#)/2 =(40-32)/2 = 8/2 = 4 Cov Bonds
DRAW STRUCTURE => A is central element, X substrates.
X
!
X-A-X
!
X
                    Answered by
            Doc
            
    The !-X is supposed to be over and under the A. 
    
                    Answered by
            Doc
            
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