Asked by Casey
Draw the Lewis structure for N2H2, a neutral molecule.
Answers
Answered by
DrBob222
N2H2.
N has 5 + 5 = 10 electrons
H has 1 + 1 = 2 electrons.
Total of 12 electrons.
I would distribute the 12 as follows:
H:N::N:H which accounts for 8. Place a pair of unshared electron on the first N and a pair of unshared electrons on the second N. That will add 4 more electrons to make the 12. Note that there are two electrons for each H and 8 electrons for each N which satisfies the rule of 8 (and 2 for H). Note also that H:N:::N:H only accounts for 10 of the electrons and if an extra pair of electrons is added to one of the N atoms, the rule of 8 is not followed.
N has 5 + 5 = 10 electrons
H has 1 + 1 = 2 electrons.
Total of 12 electrons.
I would distribute the 12 as follows:
H:N::N:H which accounts for 8. Place a pair of unshared electron on the first N and a pair of unshared electrons on the second N. That will add 4 more electrons to make the 12. Note that there are two electrons for each H and 8 electrons for each N which satisfies the rule of 8 (and 2 for H). Note also that H:N:::N:H only accounts for 10 of the electrons and if an extra pair of electrons is added to one of the N atoms, the rule of 8 is not followed.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.