Asked by LIVINUS CHIDERA
3. An isosceles triangle has sides length xcm xcm and 9cm.
B its perimeter is less than 24 and x is a whole number.
I find the lowest value of x.
II find the highest value of x
B its perimeter is less than 24 and x is a whole number.
I find the lowest value of x.
II find the highest value of x
Answers
Answered by
Steve
x+x+9 < 24
2x < 15
x < 7.5
so, x <= 7
The sides of length x must each be > 9/2, so x >= 5
5 <= x <= 7
2x < 15
x < 7.5
so, x <= 7
The sides of length x must each be > 9/2, so x >= 5
5 <= x <= 7
Answered by
rtttttt
what is the answer?
Answered by
Laura
Answers
Answered by
jijimaa
maths
Answered by
IGBANUGO
2×x+9<24=2x+9÷2<24÷2=2x+9<12
Answered by
Uhhhhhhh
X+x+9<24
2x<15
x<7 1/2
Lowest value 0
Highest 7
2x<15
x<7 1/2
Lowest value 0
Highest 7
Answered by
Chukwudi Kelvin Chiagozie
X+x+9<24
2x<15
2x<15
Answered by
Tomi
5
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