Asked by Jennifer
Solve
x^2 + 3x + 3 = 0
-1 +- sq.rt 1-4 (1)(3)
-1 +- sq.rt 1-12 =
-1 +- i sq.rt 11/2
Is this correct?
x^2 + 3x + 3 = 0
-1 +- sq.rt 1-4 (1)(3)
-1 +- sq.rt 1-12 =
-1 +- i sq.rt 11/2
Is this correct?
Answers
Answered by
Reiny
no, I don't think you are using the quadratic formula correctly.
Do you have
for ax^2 + bx + c=0
x = (-b ±√(b^2 - 4ac)/(2a) ??
then for yours
x = (-3 ±√(9-4(1)(3))/2
= (-3 ±√-3)/2 which is a complex number
Do you have
for ax^2 + bx + c=0
x = (-b ±√(b^2 - 4ac)/(2a) ??
then for yours
x = (-3 ±√(9-4(1)(3))/2
= (-3 ±√-3)/2 which is a complex number
Answered by
Jennifer
yes i have that formula
i thought i was told to just put in the numbers for the variables
i thought i was told to just put in the numbers for the variables
Answered by
Reiny
but you did not put them in the right way.
Answered by
Jennifer
ok thanks for your help
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