Asked by Chintu
Prove that 0! = 1
Answers
Answered by
Steve
It is defined that way. It makes possible the definition that
n! = n(n-1)! for all integer n>0
n! = n(n-1)! for all integer n>0
Answered by
Reiny
Suppose we have n objects.
In how many ways can I take all of them
of course the answer to that is 1 way.
but from the theory of combinations it would be
n!/( (n-n)(n!) )
= n!/(0!n!)
= 1/0!
but we know that has to be 1
1/0! = 1, this can only be true if we define 0! = 1
That is , we are forced to accept 0! = 1 if our theory of combinations and permutations is accepted.
In how many ways can I take all of them
of course the answer to that is 1 way.
but from the theory of combinations it would be
n!/( (n-n)(n!) )
= n!/(0!n!)
= 1/0!
but we know that has to be 1
1/0! = 1, this can only be true if we define 0! = 1
That is , we are forced to accept 0! = 1 if our theory of combinations and permutations is accepted.
Answered by
Chintu
Thanks for the help !
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.