24. solve the system of equations algerbraically. show all of your steps. (2 points)
y=x^(2)+2x
y=3x+20
I'm just having trouble understanding.
Please help
y=x^(2)+2x
y=3x+20
I'm just having trouble understanding.
Please help
Answers
Answered by
Steve
Since you have two values for y, just set them equal to each other:
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 0
and you're home free...
x^2+2x = 3x+20
x^2-x-20 = 0
(x-5)(x+4) = 0
and you're home free...
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