Asked by Gabbi

A box contains $7.80 in nickels, dimes, and quarters. There are 46 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coins of each kind are there?

Here is my work so far:
x + y + z = 46
x + y = z - 2
.5x + .10y + .25y = 7.80
Answered by Gabbi
Typo...
.5x + .10y + .25y = 7.80

is actually

.5x + .10y + .25z = 7.80
Answered by Steve
no, it is actually

.05x + .10y + .25z = 7.80

Now solve 'em!
Answered by Gabbi
x+y+z=46
x+y=z-2
.05x+.10y+.25z=7.80

x+y=z-2
z=x+y+2

x+y+x+y+2=46
2x+2y=44

Does this look right so far..?
Answered by Anonymous
a farmer has 500 feet of fence with which to fence a rectangular plot of land. The plot lies along a river so that only three sides need to be fenced. Estimate the largest area that can be fenc
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