Asked by Eliza
35.0mL of 0.050 M HCl is titrated with 0.050 M NH3 (Kb= 1.8 x 10^-5). The pH of the analyte solution after 15.0mL addition of NH3 titrant is?
Answers
Answered by
DrBob222
NH3 + HCl ==> NH4Cl
mols NH3 = M x L = ?
mols HCl = M x L = ?
Subtract mols HCl - mols NH3. I think HCl is in excess but you should confirm that. .
That means pH = =log (HCl).
mols NH3 = M x L = ?
mols HCl = M x L = ?
Subtract mols HCl - mols NH3. I think HCl is in excess but you should confirm that. .
That means pH = =log (HCl).
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