Question
Using heat exchange and conservation of thermal energy, determine the specific heat capacity for your metal.
So the data we have is:
Aluminium:
Mass - 0.004
Initial temp - 100C
Final temp: 32C
Water:
Mass -0.1
Initial temp - 20C
Final temp - 32C
I know that the formula is mct = mct but I don't get what I'm solving for or how to do it.
Thank you for your help!
So the data we have is:
Aluminium:
Mass - 0.004
Initial temp - 100C
Final temp: 32C
Water:
Mass -0.1
Initial temp - 20C
Final temp - 32C
I know that the formula is mct = mct but I don't get what I'm solving for or how to do it.
Thank you for your help!
Answers
assuming kilograms (please specify units)
water is 4180 J/(kg deg C)
heat into water = (0.1)4180*(32-20)
Al is C J/(kg deg C)
heat out od Al = .004(C)(100-32)
so
.004(C)(100-32)=(0.1)4180*(32-20)
water is 4180 J/(kg deg C)
heat into water = (0.1)4180*(32-20)
Al is C J/(kg deg C)
heat out od Al = .004(C)(100-32)
so
.004(C)(100-32)=(0.1)4180*(32-20)
Thank you for answering! So when I did the math I got 18,441 j/kg degree c
However the actual value is supposed to be 900.did I do the math wrong or did I just do something wrong in the experiment? Thanks!
However the actual value is supposed to be 900.did I do the math wrong or did I just do something wrong in the experiment? Thanks!
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