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Asked by melina

y=-sin^2 (1/x)
find the derivative

8 years ago

Answers

Answered by Steve
just use the chain rule twice
y = v^2(u(x))
y' = 2v v'(u) u'(x)

y' = -2sin(1/x) cos(1/x) (-1/x^2)
8 years ago

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