∫ [(e^x^2-2x)/(e^x^2)] dx
= ∫ [1 - 2x/((e^x^2))] dx
= ∫ [1 - 2x(e^(-x^2))] dx
= x - e^(-x^2) + c
check by differentiating
How do you find the anti derivative of: [(e^x^2-2x)/(e^x^2)] ?
∫ [(e^x^2-2x)/(e^x^2)]
((The e^x^2 is: e raised to x squared))
if you could explain and show the steps too, thank you
4 answers
John, how did you get that integral symbol?
Hey, yeah, cool !
I can do a long one
⌠
⌡
but it takes two lines
⌠
⌡
but it takes two lines