Question
Does 1/ln(x+1) converge or diverge?
I've tried the nth term test, limit comparison test, and integral test. All I get is inconclusive. The other tests I have (geometric series, p-series, telescoping series, alternating series, and root tests) don't apply. What can I use?!
As x-> infinity, 1/ln (x+1) approaches zero. That means that it converges.
Is that the limit you had in mind?
As x-> -1, it converges to zero
As x-> 0, it diverges, since ln 1 = 0
ln (x+1) is undefined for x<-1
No, I wondered if the sum converged, not the sequence. Sorry
I've tried the nth term test, limit comparison test, and integral test. All I get is inconclusive. The other tests I have (geometric series, p-series, telescoping series, alternating series, and root tests) don't apply. What can I use?!
As x-> infinity, 1/ln (x+1) approaches zero. That means that it converges.
Is that the limit you had in mind?
As x-> -1, it converges to zero
As x-> 0, it diverges, since ln 1 = 0
ln (x+1) is undefined for x<-1
No, I wondered if the sum converged, not the sequence. Sorry
Answers
Related Questions
n=1 series to infinity (-5^n)/n^3 does it absolutely converge, diverge or conditionally converge. Wo...
Sigma with n=1 to n= positive infinity
(x^3)* (e^(-x^4))
Does it converge or diverge and use...
Does the series converge or diverge? Use the comparison test. Thank you
((1/n)-(1/n^2))^n
For each sequence an find a number k such that nkan
has a finite non-zero limit.
(This is of use...