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find the amount of sheet metal needed to form a conical funnel of base radius 30 cm and vertical height 50 cm, allowing for a 0...Asked by Jasmine
Find the amount of sheet metal needed to form a conical funnel of base radius 30 cm and vertical height 50 cm, allowing for a 0.5 cm overlap at the join.
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Answered by
Steve
The lateral surface area is
a = 2πrs = 2πr√(r^2+h^2)
= 2π*30*√3400
= 600π√34
Assuming that the join is 0.5 cm at the base, but decreases approaching the point of the cone, the 0.5cm overlap at the base means that you have a portion of the surface area added. That amount is
0.5/(2π*30) = 1/(120π)
of the surface area. So, add an additional
1/(120π) * 600π√34 = 5√34 cm^2
a = 2πrs = 2πr√(r^2+h^2)
= 2π*30*√3400
= 600π√34
Assuming that the join is 0.5 cm at the base, but decreases approaching the point of the cone, the 0.5cm overlap at the base means that you have a portion of the surface area added. That amount is
0.5/(2π*30) = 1/(120π)
of the surface area. So, add an additional
1/(120π) * 600π√34 = 5√34 cm^2
Answered by
dinesh
Omg so easy do in grade 5 india JEE
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