Asked by Anonymous
A 1200kg fuel tank is cruising at 15m/s and doesn't notice that the 800kg car right in front of it slowed down to 10m/s.the truck runs into the car in a collision that last for 0.25s.the tanker is going at 12m/s after the collision find(a)what force did the car exert on the truck (b)what is the car velocity after collision?
Answers
Answered by
Henry
V = Vo + a*t.
12 = 15 + a*0.25, a = -12 m/s^2.
a. Fe = M*a = 1200*(-12).
b. M1*V1 + M2*V2 = M1*V3 + M2*V4.
1200*15 + 800*10 = 1200*12 + 800V4,
18,000 + 8000 = 14,400 + 800V4,
-14,400 + 26,000 = 800V4,
800V4 = 11,600, V4 = 14.5 m/s. = Velocity of the car.
12 = 15 + a*0.25, a = -12 m/s^2.
a. Fe = M*a = 1200*(-12).
b. M1*V1 + M2*V2 = M1*V3 + M2*V4.
1200*15 + 800*10 = 1200*12 + 800V4,
18,000 + 8000 = 14,400 + 800V4,
-14,400 + 26,000 = 800V4,
800V4 = 11,600, V4 = 14.5 m/s. = Velocity of the car.
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