Asked by Ralph
a police car is cruising on the right lane at 25 m/s (meters/sec.). A motorcycle, on the left lane, passes the police car at a constant 35 m/s. The police officer reacts fast and accelerates at a constant 5 m/s^2.
(a)When does he catch up?
(b)What was his velocity at that instant?
(a)When does he catch up?
(b)What was his velocity at that instant?
Answers
Answered by
drwls
At the time t after the police car is passed, the distances travelled are:
X1 (motorcycle) = 35 t (meters)
X2 (police) = 25t + (1/2)(5)t^2
(a) Set X1 = X2 and solve for t. Ignore the t=0 solution. Take the other one.
(b) V2 = 25 + 5t is the celocity of the police car. Use the appropriate value of t.
X1 (motorcycle) = 35 t (meters)
X2 (police) = 25t + (1/2)(5)t^2
(a) Set X1 = X2 and solve for t. Ignore the t=0 solution. Take the other one.
(b) V2 = 25 + 5t is the celocity of the police car. Use the appropriate value of t.
Answered by
Ralph
thank you!
Answered by
eraft
erft
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