6 black counters and 4 white counters in bag A.
7 black counters and 3 white counters in bag B.
5 black counters and 5 white counters in bag C.
Tarek takes at random a counter from bag A and puts the counter in bag B. He then takes at random a counter from bag B and put the counter in bag C.
What is the probability that there are now more black counters than white counters in bag C.
Thank you very very much.
5 answers
3/5
work out the probability of two scenarios
1. the probability of picking a black counter from bag a then a black counter from bag B
6/10 * 8/11 = 48/110
2 The probability of picking a white counter form bag A then a black counter from bag B
4/10 * 7/11 = 28/110
In both scenarios you end with a black counter to put in bag C making bad C have more black counters than white. you combine the answers and get the probability of having more black counters in Bag C
24/110 + 48/110 = 72/110
1. the probability of picking a black counter from bag a then a black counter from bag B
6/10 * 8/11 = 48/110
2 The probability of picking a white counter form bag A then a black counter from bag B
4/10 * 7/11 = 28/110
In both scenarios you end with a black counter to put in bag C making bad C have more black counters than white. you combine the answers and get the probability of having more black counters in Bag C
24/110 + 48/110 = 72/110
Thank you for explaining it so clearly. x
I’m a bit confused as to where the 24/110 came from?
yeah i agree w/ tom where does 24/110 come from do you mean 28/110??
1 answer