Asked by Joey
Prove algebraically that the difference between any two different odd numbers is an even number.
Thanks.
Thanks.
Answers
Answered by
Steve
an odd number is of the form 2k+1 where k is any integer. So, subtracting 2m+1 from 2n+1 you get
(2n+1)-(2m+1)
= 2n+1-2m-1
= 2n+2m
= 2(n+m)
any multiple of 2 is even
(2n+1)-(2m+1)
= 2n+1-2m-1
= 2n+2m
= 2(n+m)
any multiple of 2 is even
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