Asked by Joey

Prove algebraically that the difference between any two different odd numbers is an even number.

Thanks.

Answers

Answered by Steve
an odd number is of the form 2k+1 where k is any integer. So, subtracting 2m+1 from 2n+1 you get

(2n+1)-(2m+1)
= 2n+1-2m-1
= 2n+2m
= 2(n+m)

any multiple of 2 is even
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