Question
Prove algebraically that the difference between any two different odd numbers is an even number.
Thanks.
Thanks.
Answers
an odd number is of the form 2k+1 where k is any integer. So, subtracting 2m+1 from 2n+1 you get
(2n+1)-(2m+1)
= 2n+1-2m-1
= 2n+2m
= 2(n+m)
any multiple of 2 is even
(2n+1)-(2m+1)
= 2n+1-2m-1
= 2n+2m
= 2(n+m)
any multiple of 2 is even
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