Question

The 90 men that visited a restaurant take one of either pounded yam,rice and amala.10 take pounded yam and rice,19 take rice and amala and 29 take pounded yam and amala.x men take all the three menu.2x men each take only one food item.how many take all three food item

Answer 1

(2x+2x+2x)-(10+19+29)+x = 90

Hmmm. I suspect a typo.

Answer 2

The final answer is 37....The solution u gave was 21

Answer 3

you are correct. I misread the problem. Can you see where?

Answer 4

4x+58=90

Answer 5

37

Answer 6

(x-10)+(x-19) +(x-29) +x =90
4x-58=90
4x=90+58
4x=148
x=148/4
x=37

Answer 7

Please represent in a Venn diagram

Answer 8

The answer is 8 Since rice only =poundo only=amala only=2x then 2x+2x+2x+29-x+19-x+10-x+x=90 4x+58=90 4x=90-58 4x=32=>x=8

Answer 9

ADEDOYIN FEYISARA OLALERE,
You did not capture the number of those that take only one food item... I.e the supposed 2x in your algorithm.
Can you relate ?

Answer 10

The answer is 8.
7x + 58 - 3x = 90
4x = 90 - 58
X = 32/4
X= 8.

Answer 11

I don't think the answer is 37 because if u sum everything within d Venn diagram it must give 90 , so 8 should b d correct answer .

Answer 12

The correct answer is 8.If you add all the values in the ven diagram it will give you 90.

Answer 13

The answer should be 8

Answer 14

The answer should be _37_

Answer 15

The answer is 8. Because (2x x 3) + (10-x) + (29-x) + (19+x) + x = 90
This implies, 4x = 32
x = 8.

Answer 16

The answer is 8
2x+2x+2x+29-x+19-x+10-x+x=90
4x+58=90
4x=90-58=32
Divide both sides by 4
4x/4=32/
=8//

Answer 17

The answer is 7