Asked by Rilwan

The 90 men that visited a restaurant take one of either pounded yam,rice and amala.10 take pounded yam and rice,19 take rice and amala and 29 take pounded yam and amala.x men take all the three menu.2x men each take only one food item.how many take all three food item

Answers

Answered by Steve
(2x+2x+2x)-(10+19+29)+x = 90

Hmmm. I suspect a typo.
Answered by Rilwan
The final answer is 37....The solution u gave was 21
Answered by Steve
you are correct. I misread the problem. Can you see where?
4x+58=90
37
Answered by James
(x-10)+(x-19) +(x-29) +x =90
4x-58=90
4x=90+58
4x=148
x=148/4
x=37
Answered by Teg
Please represent in a Venn diagram
Answered by Vincent
The answer is 8 Since rice only =poundo only=amala only=2x then 2x+2x+2x+29-x+19-x+10-x+x=90 4x+58=90 4x=90-58 4x=32=>x=8
Answered by Ibrahim
ADEDOYIN FEYISARA OLALERE,
You did not capture the number of those that take only one food item... I.e the supposed 2x in your algorithm.
Can you relate ?
Answered by Jamgbadi Philip
The answer is 8.
7x + 58 - 3x = 90
4x = 90 - 58
X = 32/4
X= 8.
Answered by Erinfolami
I don't think the answer is 37 because if u sum everything within d Venn diagram it must give 90 , so 8 should b d correct answer .
Answered by Abdulganius
The correct answer is 8.If you add all the values in the ven diagram it will give you 90.
Answered by Moibi Ayobamidele
The answer should be 8
Answered by Moibi Ayobamidele
The answer should be _37_
Answered by S. B. Salaudeen
The answer is 8. Because (2x x 3) + (10-x) + (29-x) + (19+x) + x = 90
This implies, 4x = 32
x = 8.
Answered by Amaechi Lilian
The answer is 8
2x+2x+2x+29-x+19-x+10-x+x=90
4x+58=90
4x=90-58=32
Divide both sides by 4
4x/4=32/
=8//
Answered by Anonymous
The answer is 7
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