Question
were must be the pivot situated on a straight lever 2m long,if a downward effort of 200N at one end is to lift a mass of 50kg at the other end.state the distance from the effort.
Answers
Scott
the weight (force) of 50 kg is
... 50 kg * g
... g is the acceleration by gravity
200 * d = 50 * g * (2 - d)
... 50 kg * g
... g is the acceleration by gravity
200 * d = 50 * g * (2 - d)