Question
when loading a toy launcher, a spring is pulled back 15 cm. the spring is known to have a spring constant of 315 N/m. A small object of mass 4.46 g is place at the end of the spring. What acceleration will the object experience the instant the spring is released?
Answers
f = m a ... a = f / m
a = (315 N * .15) / .00446 kg
a is in m/s^2
a = (315 N * .15) / .00446 kg
a is in m/s^2
Could you explain why you multiplied the constant by the .15m?
that is the compression of the spring
the more it's compressed, the greater the force
the more it's compressed, the greater the force
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