when loading a toy launcher, a spring is pulled back 15 cm. the spring is known to have a spring constant of 315 N/m. A small object of mass 4.46 g is place at the end of the spring. What acceleration will the object experience the instant the spring is released?

3 answers

f = m a ... a = f / m

a = (315 N * .15) / .00446 kg

a is in m/s^2
Could you explain why you multiplied the constant by the .15m?
that is the compression of the spring

the more it's compressed, the greater the force