Asked by Anon
A water balloon launcher launches a balloon straight up at a flying kite. If the kite is hovering 75.0 meters off the ground, and the balloon hits it on its upward trajectory with a velocity of 12.2m/s,
a) What was the launch velocity of the balloon
a) What was the launch velocity of the balloon
Answers
Answered by
bobpursley
total energy at balloon = launch energy
mgh+ 1/2 m (12.2)^2=1/2 m vlaunch^2
solve for vlaunch
mgh+ 1/2 m (12.2)^2=1/2 m vlaunch^2
solve for vlaunch
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