When a person got onto an airplane, she brought with her a half-full 1.0000 L aluminum water bottle that was closed inside the airport at standard pressure and a temperature of 26.000 C. After the plane takes off and climbs to 36,000. feet, the cabin pressure is at 0.82000 atm and the cabin temperature is 26.000 C. Assume her water bottle and its contents always take the temperature of its surroundings.
a) What would happen if she opened the water bottle for a drink?
P1V1 = P2V2
(1) (.05) = (.82) (V2) = .609 L
I am assuming there would be slightly more water?
b) What if the cabin pressure was at 0.82000 atm and the cabin temperature was at -28 C? (Ignore the expansion of frozen water.)
V1/T1 = V2/T2
0.5/299 K = V2/245 K
The volume would slightly decrease?
I am not really sure if this is what I am supposed to get out of these questions. They seem a little odd, but based off of P1V1 = P2V2 and V1/T1 = V2/T2. That seems to be correct.
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(a) but when she opens the bottle the air inside is still at 1 atm so must escape out the open top--> whoosh !
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