Asked by Dave

A 10.0000 g block of aluminum is heated and placed in a stream of oxygen gas, resulting in the formation of aluminum oxide on the surface of the block.
The block is cooled and weighed and found to have a mass of 11.6471 g.
The block is then placed in a weak acid to remove the aluminum oxide layer from the block.
After a of the aluminum oxide is removed, the block is weighed and found to have a mass of 8.1471 g.
What is the empirical formula of aluminum oxide?



I know how to do the whole process for finding the empirical formula, but I am confused what is the mass of aluminum and what is the mass of oxygen that we start with?
I need to know this in order to multiply it by the molar mass.
Answered by DrBob222
You didn't read my earlier response did you. Proof your post or you'll never get it answered. A word or some words are missing from the beginning of sentence 3.
Answered by DrBob222
OK. I see you did read my earlier post but didn't understand it. In sentence 3, "After a of the aluminum oxide is removed......" doesn't make sense. After a what is removed?
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