Asked by barma isa ferobe
If p varies as the cube of and q varies directly as the the square of r what is the relationship between paund r
Answers
Answered by
Steve
The only way I can make sense of what you wrote is to interpret it as
p = mq^3
q = nr^2
p = m(nr^2)^3 = mn^3 r^6 = kr^k
p varies directly as the 6th power of r.
p = mq^3
q = nr^2
p = m(nr^2)^3 = mn^3 r^6 = kr^k
p varies directly as the 6th power of r.
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