Question
To find the length of the curve defined by y = 5x^3+9x from the point (-3,-162) to the point (1,14), you’d have to compute the integral [a,b] f(x)dx
where
a =
b =
f(x) =
where
a =
b =
f(x) =
Answers
Bosnian
a
L = ∫ [ sqrt 1 + ( y´ )^ 2 ] dx
b
In this case:
y´= 3 * 5 * x ^ 2 + 9 = 15 x ^ 2 + 9
1 + ( y´ )^ 2 = 1 + ( 15 x ^ 2 + 9 ) ^ 2
a = - 3
b = 1
f(x) = sqroot [ 1 + ( 15 x ^ 2 + 9 ) ^ 2 ]
L = ∫ [ sqrt 1 + ( y´ )^ 2 ] dx
b
In this case:
y´= 3 * 5 * x ^ 2 + 9 = 15 x ^ 2 + 9
1 + ( y´ )^ 2 = 1 + ( 15 x ^ 2 + 9 ) ^ 2
a = - 3
b = 1
f(x) = sqroot [ 1 + ( 15 x ^ 2 + 9 ) ^ 2 ]