Question

A bungee jumper with mass 69.5 kg jumps from a high bridge.
After reaching his lowest point, he oscillates up and down,
hitting a low point eight more times in 36.6 s. He finally
comes to rest 24.3 m below the level of the bridge. Calculate
the spring constant of the bungee cord.

Answer 1

The frequency is 8/36.6 = 0.2185 Hz

That equals [1/(2 pi)]sqrt(k/m)

You know m = 69.5 kg. Solve for k

The 24.3 m number you do not need.

Answer 2

Thanks for the timely help