Asked by Jay111
For x [–14,13] the function f is defined by
f(x)=(x^3)(x+6)^4
On which two intervals is the function increasing (enter intervals in ascending order)?
I got increasing intervals between [-14, -6], but can't find the other increasing interval. I believe it is [-3, 13] but I get the answer is wrong. Thanks again.
f(x)=(x^3)(x+6)^4
On which two intervals is the function increasing (enter intervals in ascending order)?
I got increasing intervals between [-14, -6], but can't find the other increasing interval. I believe it is [-3, 13] but I get the answer is wrong. Thanks again.
Answers
Answered by
drwls
The places where the function changes from increasing to decreasing are where f'(x) = 0
f'(x) = 3x^2(x+6)^4 + 4(x+6)^3*x^3
= (x+6)^3 [7x^3 +18x^2]
I can see that becoming zero at x=0, x=-6, and x = -18/7, but not at x=-3
recheck your numbers and mine
f'(x) = 3x^2(x+6)^4 + 4(x+6)^3*x^3
= (x+6)^3 [7x^3 +18x^2]
I can see that becoming zero at x=0, x=-6, and x = -18/7, but not at x=-3
recheck your numbers and mine
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.