Asked by Anne
Consider the given function and the given interval.
f(x) = (x − 3)^2, [2, 5]
(a) Find the average value fave of f on the given interval.
fave =
(b) Find c such that fave = f(c).
c = (smaller value)
c= (larger value)
f(x) = (x − 3)^2, [2, 5]
(a) Find the average value fave of f on the given interval.
fave =
(b) Find c such that fave = f(c).
c = (smaller value)
c= (larger value)
Answers
Answered by
Steve
recall that the average value of f(x) on [a,b] is
(∫[a,b] f(x) dx)/(b-a)
now just plug and chug.
(∫[a,b] f(x) dx)/(b-a)
now just plug and chug.
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