Asked by JENNIFER
THE QUESTION ASKS TO CALCULATE THE AMOUNT (IN GRAMS) OF CARBON DIOXIDE FROM THE AMOUNT OF SODIUM BICARBONATE THAT YOU USED IN THE REACTION Run 1.
The reaction of citric acid and sodium bicarbonate is written as
H3C6H5O7(aq) + 3 NaHCO3(aq) → Na3C6H5O7(aq) + 3 H2O(l) + 3 CO2(g)
Here is what I got in reaction run 1:
1.02G SODIUM BICARBONATE
0.77G OF CITRIC ACID
0.24G MAS OF CARBON DIOXIDE
*1.02g of sodium bicabonate*1mol /84.01g/mol of sodium bicarbonate= 0.0121 mol
* 0.0121 mol of sodium bicarbonate*3 mol of Carbon dioxide/3 mol of sodium bicarbonate=0.0121 mol of carbon dioxide
* 0.0121 mol of carbon dioxide*44.01g/1 mol of carbon dioxide/1 mol of carbon dioxide- 0.5g/mol of carbon dioxide.
Is this correct?
The reaction of citric acid and sodium bicarbonate is written as
H3C6H5O7(aq) + 3 NaHCO3(aq) → Na3C6H5O7(aq) + 3 H2O(l) + 3 CO2(g)
Here is what I got in reaction run 1:
1.02G SODIUM BICARBONATE
0.77G OF CITRIC ACID
0.24G MAS OF CARBON DIOXIDE
*1.02g of sodium bicabonate*1mol /84.01g/mol of sodium bicarbonate= 0.0121 mol
* 0.0121 mol of sodium bicarbonate*3 mol of Carbon dioxide/3 mol of sodium bicarbonate=0.0121 mol of carbon dioxide
* 0.0121 mol of carbon dioxide*44.01g/1 mol of carbon dioxide/1 mol of carbon dioxide- 0.5g/mol of carbon dioxide.
Is this correct?
Answers
Answered by
DrBob222
Almost.
You were asked to calculate the mass CO2 generated. The last line should read
"0.5 g of carbon dioxide" 05 g/mol is not right. The unit /mol canceled in your previous step.
You were asked to calculate the mass CO2 generated. The last line should read
"0.5 g of carbon dioxide" 05 g/mol is not right. The unit /mol canceled in your previous step.
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