Asked by Anonymous
A car drive straight of the edge of a cliff that is 54m high. The police note that the point of impact is 130m from the base of the cliff. How fast was the car travelling when it went off the cliff.
Answers
Answered by
Henry
h = 0.5g*t^2.
54 = 4.9t^2, t = 3.32 s. = Fall time.
d = V*t, 130 = V*3.32, V = ?.
V in m/s.
54 = 4.9t^2, t = 3.32 s. = Fall time.
d = V*t, 130 = V*3.32, V = ?.
V in m/s.
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