Asked by Scarlet

In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.
What percent of the square’s area is the area of the new rectangle?
What percentage of the square’s perimeter is the perimeter of the new rectangle?

Answers

Answered by Henry
Let S1 = S2 = S3 = S4 = 10 units.
A1 = L*W = 10 * 10 = 100 sq. units.

S1 = S3 = 1.5*10 = 15.
S2 = S4 = 0.5*10 = 5.
A2 = L*W = 15 * 5 = 75 sq. units.

A2/A1 = 75/100 = 0.75 = 75%.

P2/P1 = (2L+2W)/(4*10) = (2*15+2*5) = 40/40 = 1.00 = 100%.
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