Asked by Scarlet
In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.
What percent of the square’s area is the area of the new rectangle?
What percentage of the square’s perimeter is the perimeter of the new rectangle?
What percent of the square’s area is the area of the new rectangle?
What percentage of the square’s perimeter is the perimeter of the new rectangle?
Answers
Answered by
Henry
Let S1 = S2 = S3 = S4 = 10 units.
A1 = L*W = 10 * 10 = 100 sq. units.
S1 = S3 = 1.5*10 = 15.
S2 = S4 = 0.5*10 = 5.
A2 = L*W = 15 * 5 = 75 sq. units.
A2/A1 = 75/100 = 0.75 = 75%.
P2/P1 = (2L+2W)/(4*10) = (2*15+2*5) = 40/40 = 1.00 = 100%.
A1 = L*W = 10 * 10 = 100 sq. units.
S1 = S3 = 1.5*10 = 15.
S2 = S4 = 0.5*10 = 5.
A2 = L*W = 15 * 5 = 75 sq. units.
A2/A1 = 75/100 = 0.75 = 75%.
P2/P1 = (2L+2W)/(4*10) = (2*15+2*5) = 40/40 = 1.00 = 100%.
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