Question

In a square, one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter.
What percent of the square’s area is the area of the new rectangle?
What percentage of the square’s perimeter is the perimeter of the new rectangle?

Answer 1

Let S1 = S2 = S3 = S4 = 10 units.
A1 = L*W = 10 * 10 = 100 sq. units.

S1 = S3 = 1.5*10 = 15.
S2 = S4 = 0.5*10 = 5.
A2 = L*W = 15 * 5 = 75 sq. units.

A2/A1 = 75/100 = 0.75 = 75%.

P2/P1 = (2L+2W)/(4*10) = (2*15+2*5) = 40/40 = 1.00 = 100%.

Answer 2

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