Under the same condition of temp.and pressure hydrogen gas diffuses 8 times as fast as gas y.calculate the relative molecular mass of gas y.(R.M

Question

M_2

Answer 1

What is Graham's law? https://www.google.com/search?q=Graham%27s+law&ie=utf-8&oe=utf-8

8/1=sqrt(2/MM)
MM=32 Oxygen O2?

If you mean by RMM compared to H2, then it is 64

Answer 2

Thanks, DrBob: the first line should read
8/1=sqrt(MM/2)

Answer 3

Under the same condition of temperature and pressure , hydrogen diffuses 8times as fast as gas Y, calculate the relative molecular mass of Y.(R.M.M of H2= 2)

Answer 4

I can't really get the answer of the question

Answer 5

Ra/Rb=√Mb/Ma
Ra = 8Y
Rb=Y
Ma=2
8Y/Y=√Mb/2
8=√Mb/2
(8)^2=Mb/2
Mb=2×64
Mb=128