Question

Factor each completely;

3n^2+21n

6n^2+18n

not quite sure how to factor completely on problems with that format.

Answers

Bosnian
3 n ^ 2 + 21 n =

3 n * n + 3 n * 7 =

3 n ( n + 7 )


6 n ^ 2 + 18 n =

6 n * n + 6 n * 3 =

6 n ( n + 3 )

Related Questions