Asked by Anonymous

factor completely a^9+b^12 c^15

13 years ago

Answered by Reiny

does not factor using rationals.

13 years ago

Answered by Anonymous

yes there's an a

13 years ago

Answered by Steve

= (a^3)^3 + (b^4c^5)^3
= (a^3 + b^4c^5)(x^6 - a^3b^4c^5 + b^8c^10)

13 years ago

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