Question
factor completely a^9+b^12 c^15
Answers
Reiny
does not factor using rationals.
Anonymous
yes there's an a
Steve
= (a^3)^3 + (b^4c^5)^3
= (a^3 + b^4c^5)(x^6 - a^3b^4c^5 + b^8c^10)
= (a^3 + b^4c^5)(x^6 - a^3b^4c^5 + b^8c^10)