Asked by Billy
If a farmer has 90 animals in a field.4/9 are sheep,1/3 are cows,1/10 are horses and the rest are pigs.How many pigs are there?
Answers
Answered by
Billy
I don't know the answer
Answered by
PsyDAG
4/9*90 = 40 are sheep, 1/3* 90 =30 are cows, 1/10*90 = 9 are horses. What is left?
Answered by
Ms. Sue
First you need to change these fractions to equivalent fractions with the same denominator. The smallest number divisible by 9, 3, and 10 is 90
4/9 = 40/90
1/3 = 30/90
1/10 = 9/90
Add them together and the sum is 79/90. 90/90 - 79/90 = 11/90
11 are pigs.
4/9 = 40/90
1/3 = 30/90
1/10 = 9/90
Add them together and the sum is 79/90. 90/90 - 79/90 = 11/90
11 are pigs.
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