Question
A spherical balloon remains spherical as it is slowly inflated. The radius of the balloon r (in cm) at time t (in seconds) satisfies the differential equation.
Dr/dt = k/r^2
where k is a positive constant.
When the radius is 3 cm, the radius is increasing at the rate of 5/36pi use this fact to find k.
Dr/dt = k/r^2
where k is a positive constant.
When the radius is 3 cm, the radius is increasing at the rate of 5/36pi use this fact to find k.
Answers
?? Just plug in the numbers:
at r=3,
dr/dt = 5π/36 = k/9
k = 5π/4
at r=3,
dr/dt = 5π/36 = k/9
k = 5π/4
Related Questions
A spherical balloon expands uniformly as it is inflated. The radius of the balloon in r meters at ti...
A spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 2cm/m...
A spherical balloon has a 14-in. diameter when it is fully inflated. Half of the air is let out of...