Question
A spherical balloon is being blow up so that its volume increases at a rate of 2cm^3 per second. Find the rate at which the radius increases when the volume of the balloon is 100cm^3
Answers
v = 4/3 πr^3
dv/dt = 4πr^2 dr/dt
when v = 100, r = ∛(3v/4π)
so now you have
100 = 4π∛(300/4π) dr/dt
dr/dt ≈ 2.76 cm/s
dv/dt = 4πr^2 dr/dt
when v = 100, r = ∛(3v/4π)
so now you have
100 = 4π∛(300/4π) dr/dt
dr/dt ≈ 2.76 cm/s
Related Questions
Air is being pumped into a spherical balloon so that its volume increases at a rate of 90{cm}^3/s. H...
A spherical balloon is being inflated in such a way that its radius increases at a rate of 3 cm/min....
Air is pumped into a balloon such that its volume increases at the rate of 75cm^3 per second. It is...
A spherical balloon is blown up so that it's volume increases constantly at the rate of 2cm^3 per se...