Asked by Fostine Wathenya
A spherical balloon is being blow up so that its volume increases at a rate of 2cm^3 per second. Find the rate at which the radius increases when the volume of the balloon is 100cm^3
Answers
Answered by
oobleck
v = 4/3 πr^3
dv/dt = 4πr^2 dr/dt
when v = 100, r = ∛(3v/4π)
so now you have
100 = 4π∛(300/4π) dr/dt
dr/dt ≈ 2.76 cm/s
dv/dt = 4πr^2 dr/dt
when v = 100, r = ∛(3v/4π)
so now you have
100 = 4π∛(300/4π) dr/dt
dr/dt ≈ 2.76 cm/s
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