Asked by nia
A 1000 g sample of metal with a specific heat of 0.50 J/goC is heated to 100.0oC and then placed in a 50.0 g sample of water at 20.0oC. (Hint: Specific heat of water at 20.0oC is 4.182 J/goC). What is the final temperature of the metal and the water? Write your answer to the correct number of significant figures in scientific notation.
Answers
Answered by
Scott
heat gained by water equals heat lost by metal
50.0 * (t - 20.0) * 4.182 =
... 1000 * (100.0 - t) * 0.50
50.0 * (t - 20.0) * 4.182 =
... 1000 * (100.0 - t) * 0.50
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.