Asked by Allie

Given: ∆AKL, AK = 9
m∠K = 90o
m∠A = 60 °
Find: The perimeter of ∆AKL
The area of ∆AKL

for this one i got 81 for the perimeter

side a 6 and side b is 12
Answered by Allie
for the area i got 36
(right?)
Answered by Steve
in a 30-60-90 right triangle, the ratio of the sides is 1:√3:2

m∠L = 30°, so the short leg is 9. The sides are thus

9,9√3,18 and the perimeter is 27+9√3

Looks like you need to review the standard triangles...
Answered by Jerry
how about area?
Answered by anonymous
P = 27 + 9(sqrt 3)
A = (81 sqrt 3) / 2
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